A car was travelling at a speed of 10 m/s. After the brakes were applied, it start to decelerate at a rate of 2 $m / s^{2}$ and finally came to rest. Find the distance traveled by the car before coming to rest.

10 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

15 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

35 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 25 m
Initial speed of the car $u = 10 m / s$
Final speed of the car $v = 0 m / s$
Acceleration (or retardation) of the car $a = - 2 m / s$
Using $v^{2} - u^{2} = 2 a S$
$∴$ $0 - 10^{2} = 2 (- 2) S$
$⟹ S = \frac{100}{2 \times 2} = 25 m$

Suggest Corrections

Similar questions

Q. A car, moving at 1.5

m s^{- 1}

applies brakes and comes to rest in

2 s

. If the same car travels at double the speed, what time would it take to come to rest after applying brakes?

Q. A car starts from rest and accelerates at

for 4s. It then moves at a constant velocity for next

1 m s^{- 2}

, then decelerates at

2.0 m s^{- 2}

and finally comes to rest . The total distance traveled by the car is

Q. A car travels with a uniform velocity of

25 m s^{- 1}

for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. The distance which the car travels before the brakes are applied is equal to

A car travels with a uniform velocity of 25 $m s^{- 1}$ for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s.Find:(i) the distance which the car travels before the brakes are applied,(ii) the retardation,and (iii) the distance travelled by the car after applying the brakes.

a car travels with a uniform velocity of 20m/s for 5 seconds.the brakes are applied and the car is uniformly retarted.it comes to rest in further 8seconds.calculatethe distance travelled before the brakes are applied and the distance covered after the brakes are applied.find its average speed

Join BYJU'S Learning Program

A car was travelling at a speed of 10 m/s. After the brakes were applied, it start to decelerate at a rate of 2 m/s2 and finally came to rest. Find the distance traveled by the car before coming to rest.

The correct option is A 25 mInitial speed of the car u=10 m/sFinal speed of the car v=0 m/sAcceleration (or retardation) of the car a=−2 m/sUsing v2−u2=2aS∴ 0−102=2(−2)S⟹ S=1002×2=25 m

A car was travelling at a speed of 10 m/s. After the brakes were applied, it start to decelerate at a rate of 2 $m / s^{2}$ and finally came to rest. Find the distance traveled by the car before coming to rest.

The correct option is A 25 m
Initial speed of the car $u = 10 m / s$
Final speed of the car $v = 0 m / s$
Acceleration (or retardation) of the car $a = - 2 m / s$
Using $v^{2} - u^{2} = 2 a S$
$∴$ $0 - 10^{2} = 2 (- 2) S$
$⟹ S = \frac{100}{2 \times 2} = 25 m$