A car which has an initial velocity of 4 m/s accelerates at the rate of $2 {m/s}^{2}$ for 5 seconds. What will be the distance (in $m$ ) that it covers in these 5 seconds ?

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Solution

$u = 4 m/s, a = 2 {m/s}^{2}, t = 5 s$

$s = u t + \frac{1}{2} a t^{2} = 4 \times 5 + \frac{1}{2} \times 2 \times 5^{2} = 20 + 25 = 45 m$

Hence the correct option is (b).

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A car which has an initial velocity of 4 m/s accelerates at the rate of 2 m/s2 for 5 seconds. What will be the distance (in m) that it covers in these 5 seconds ?

u=4 m/s, a=2 m/s2, t=5s s=ut+12at2=4×5+12×2×52=20+25=45 m Hence the correct option is (b).

A car which has an initial velocity of 4 m/s accelerates at the rate of $2 {m/s}^{2}$ for 5 seconds. What will be the distance (in $m$ ) that it covers in these 5 seconds ?

$u = 4 m/s, a = 2 {m/s}^{2}, t = 5 s$

$s = u t + \frac{1}{2} a t^{2} = 4 \times 5 + \frac{1}{2} \times 2 \times 5^{2} = 20 + 25 = 45 m$

Hence the correct option is (b).