A car which has an initial velocity of $4 m/s$ accelerates at the rate of $2 {m/s}^{2}$ for $5 s$ . What will be the distance (in $m$ ) that it covers in these $5 s$ ?

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Solution

$u = 4 m/s, a = 2 {m/s}^{2}, t = 5 s$

$s = u t + \frac{1}{2} a t^{2} = 4 \times 5 + \frac{1}{2} \times 2 \times 5^{2} = 20 + 25 = 45 m$

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