A car with a steering wheel of radius $25 c m$ is rotated with two anti-parallel forces of magnitude $5 N$ each. Calculate the moment of the couple.

250 N m

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125 N m

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1.25 N m

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2.5 N m

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Solution

The correct option is D $2.5 N m$
Given,
Radius of steering wheel $= 25 c m = 0.25 m$
Diameter of steering wheel (D) $= 20.25 = 0.5 m$
Magnitude of each force (F) $= 5 N$
Two anti-parallel forces of the same magnitude form a couple. So, moment of couple $= F \times D = 5 N \times 0.5 m = 2.5 N m$ .
Thus, the moment of couple on the steering wheel is $2.5 N m$ .

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A car with a steering wheel of radius 25 cm is rotated with two anti-parallel forces of magnitude 5 N each. Calculate the moment of the couple.

A car with a steering wheel of radius $25 c m$ is rotated with two anti-parallel forces of magnitude $5 N$ each. Calculate the moment of the couple.