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Question

A carbon compound containing carbon and oxygen has molar mass equal to 288. On analysis it is found to contain 50% by mass of each element. Therefore, molecular formula of the compound is:

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Solution

ElementAtomic Mass Relative no. of atoms Simplest Ratio Whole no. Ratio
C (50%)12 4.166 1.33 1.33×3=4
O (50%) 16 3.125 1 1×3=3
Empirical formula= C4O3
Mass= (4×12)+(3×16)=96
n=Molecular massEmpirical mass=28896=3
Molecular formula= n× Empirical formula
=3(C4O3)
=C12O9 .

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