A carbon compound on analysis gives the following percentage composition. Carbon 14.5 %, hydrogen 1.8 % chlorine 64.6 %, oxygen 19.24 %. The empirical formula of the compound is:
A
C2H3Cl3O2
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B
C2HCl3O4
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C
C2H2Cl3O3
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D
C2H4Cl3O2
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Solution
The correct option is AC2H3Cl3O2 Percentage compostion of the elements present in the compound, C : H : Cl : O = 14.5 : 1.8 : 64.46 : 19.24
Dividing by molar mass we get the mole ratio as, C : H : Cl : O = 1.21 : 1.8 : 1.81 : 1.2
Dividing by the smallest number and converting the same to whole numbers, we get the simplest whole number ratio. C : H : Cl : O = 2 : 3 : 3 : 2