Total number of all possible outcomes= 52
(i) Number of spade cards = 13
Number of aces = 4 (including 1 of spade)
Therefore, number of spade cards and aces = (13 + 4 − 1) = 16
∴ P( getting a spade or an ace card) =
(ii) Number of red kings = 2
∴ P( getting a red king) =
(iii) Total number of kings = 4
Total number of queens = 4
Let E be the event of getting either a king or a queen.
Then, the favourable outcomes = 4 + 4 = 8
∴ P( getting a king or a queen) = P (E) =
(iv) Let E be the event of getting either a king or a queen. Then, ( not E) is the event that drawn card is neither a king nor a
queen.
Then, P(getting a king or a queen ) =
Now, P (E) + P (not E) = 1
∴ P(getting neither a king nor a queen ) =