Question

A card is drawn at random from a well shuffled deck of 52 cards. Find the probability of getting a card bearing a number greater than 2 but less than 9.

• A. $\frac{1}{13}$
• B. $\frac{6}{13}$
• C. $\frac{4}{13}$
• D. $\frac{5}{13}$

Answer 1

The correct option is B $\frac{6}{13}$

The cards bearing a number greater than 2 but less than 9 are 3, 4, 5, 6, 7, and 8.
Each card bearing any of the above number is of 4 suits diamond, spade, club or heart.
Thus, the number of favourable outcomes = 6 × 4 = 24
For an event $\text{E, Probability P(E)}$ $=\frac{\text{Number of outcomes favourable to E}}{\text{Number of all possible outcomes of the experiment}}$
$\therefore$ Probability (bearing a number greater than 2 but less than 9)
$=\frac{24}{52}=\frac{6}{13}$