Question

A card is drawn is from pack of 52 cards. Find the probability of drawing card which is neither $2$ nor $3$.

• A. $\frac{9}{13}$
• B. $\frac{10}{13}$
• C. $\frac{11}{13}$
• D. $\frac{12}{13}$

Answer 1

The correct option is C $\frac{11}{13}$

Total number of cards $=52$

Number of outcomes$=52-8=44$

There are $8$ cards that are $2^{\prime }sand{3}^{\prime }s$ in a pack of 52 cards.

$P\left(A\right)=\frac{Numberoffavorableoutcomes}{TotalNumberofpossibleoutcomes}$

$\therefore P\left(A\right)=\frac{44}{52}=\frac{11}{13}$

Hence option $C$ is correct.