Question

A carnot engine has the same efficiency between (i) $100K$ and $500K$ and (ii)$T$ and $900K$. Find $T$.

• A. $200K$
• B. $190K$
• C. $180K$
• D. none of these

Answer 1

The correct option is C $180K$

The carnot efficiency is given as $\eta =1-\frac{T_2}{T_1}$. Here $T_1$ is the temperature of the source and $T_2$ is the temperature of the sink.
Thus we get-
$1-\frac{100}{500}=1-\frac{T}{900}$
or
$T=\frac{900}{5}=180K$