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Question

A Carnot engine, having an efficiency of η=1/10 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is

A
90 J
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B
99 J
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C
100 J
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D
1 J
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Solution

The correct option is A 90 J
Given, η=110
η=Desired effectwork input=WoutQ2=Q2Q1Q2
Where, Q1 is the heat at higher temperature and Q2 heat at lower temperature

In case of refrigerator Q2 is desired and work input is Q2Q1=W. Where, W is the work done on the system
β=Desired effectwork input=Q1Q2Q1
1β=Q2Q11(1)
η=1Q1Q2=110
Q1Q2=910 put in equation 1 we get
1β=1091=19β=9
9=Q1W=Q110
Q1=90 J

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