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Carnot Cycle

A carnot engi...

Question

A carnot engine operates between two reservoirs of temperature 900 $K$ and 300 $K$ . The engine performs 1200 $J$ of work per cycle. The heat energy in ( $J$ ) delivered by the engine to the low temperature reservoir, in a cycle, is

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Solution

$\begin{matrix} η = 1 - \frac{T_{2}}{T_{1}} = 1 - \frac{300}{900} = \frac{2}{3} Given, W = 1200 J From conservation of energy Q_{1} - Q_{2} = W η = \frac{Q_{1} - Q_{2}}{Q_{1}} = \frac{W}{Q_{1}} ⟹ Q_{1} = 1800 J \Rightarrow Q_{2} = Q_{1} - W = 600 J \end{matrix}$

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