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Heat Capacity

A Carnot engi...

Question

A Carnot engine takes 100 calories of heat in each cycle from the source at high temperature at 400 K and gives 80 calories of into the sink.The temperature of sink is

A

500 K

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B

300 K

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C

480 K

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D

320 K

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Solution

The correct option is D 320 K
Work done $W = Q_{h} - Q_{c} = 100 - 80 = 20 c a l$
Efficiency, $η = \frac{W}{Q_{h}} = 1 - \frac{T_{c}}{T_{h}}$
$\frac{20}{100} = 1 - \frac{T_{c}}{400}$
$T_{c} = 0.8 (400) = 320 K$

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