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Question

A Carnot engine takes in 3000 kcal of heat from a reservoir at 627C and gives it to a sink at 27C. The work done by the engine is

A
4.2×106J
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B
8.4×106J
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C
16.8×106J
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D
Zero
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Solution

The correct option is B 8.4×106J
Given : Q1=3000×103cal=3×106cal
T1=627C=627+273=900 K
T2=27C=27+273=300 K
Since Q1Q2=T1T2Q2=T2T1×Q1
Q2=300900×3×106=106cal
work done W=Q1Q2
=3×106106=2×106cal
=2×106×4.2 J=8.4×106J.

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