A carnot engine, whose efficiency is 40% takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency 60%. Then, the intake temperature for the same exhaust (sink) must be
A
efficiency of carnot engine cannot be made larger than 50%
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B
1200K
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C
750K
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D
600K
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Solution
The correct option is C750K Let the sink temperature be Ts, then 1−Ts500=0.4∴Ts=300K For second case, 1−300T=0.6 T=3000.4=750K