wiz-icon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

A Carnot engine whose sink is at 300 K has an efficiency of 40%. By how much should the temperature of source be increased so as to increase its efficiency by 50% of original efficiency?

A
325 K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
250 K
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
380 K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
275 K
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 250 K
Efficiency of the carnot engine, η=T1T2T1
where T1=Source temperature
T2 = sink temperature
0.40=T1300T1
T1=500 K
Since η is increased by 50% , the new efficiency will be 60%
0.60=T1300T1
T1=750 K
Increase in Temprature=750500=250 K

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Carnot Cycle
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon