Question

A Carnot engine whose source is at 400 K takes 200 cal of heat and rejects 150 cal to the sink. What is the temperature of the sink?

• A. 800 K
• B. 400 K
• C. 300 K
• D. cannot say

Answer 1

The correct option is C 300 K

$\frac{Q_2}{Q_1}=\frac{T_2}{T_1}$
Therefore $T_2=\frac{Q_2}{Q_1}\times T_1=\frac{150}{200}\times 400=300K$