A carnot engine works between $600 K a n d 300 K$ . In each cycle of operation, the engine draws $1000 J$ of heat energy from the source. The efficiency of the engine is

50%

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70%

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20%

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80%

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Solution

The correct option is B 50%
Efficiency of heat engine( $η$ ) is:
$η = (1 - \frac{T_{2}}{T_{1}}) \times 100$ % where $T_{1}$ is the temp of the source and $T_{2}$ is the temp of the sink.
$∴ η = 1 - \frac{300}{600} \times 100 = \frac{1}{2} \times 100 = 50$ %

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A carnot engine works between 600K and 300K. In each cycle of operation, the engine draws 1000J of heat energy from the source. The efficiency of the engine is

The correct option is B 50%Efficiency of heat engine(η) is:η=(1−T2T1)×100% where T1 is the temp of the source and T2 is the temp of the sink.∴η=1−300600×100=12×100=50%

A carnot engine works between $600 K a n d 300 K$ . In each cycle of operation, the engine draws $1000 J$ of heat energy from the source. The efficiency of the engine is

The correct option is B 50%
Efficiency of heat engine( $η$ ) is:
$η = (1 - \frac{T_{2}}{T_{1}}) \times 100$ % where $T_{1}$ is the temp of the source and $T_{2}$ is the temp of the sink.
$∴ η = 1 - \frac{300}{600} \times 100 = \frac{1}{2} \times 100 = 50$ %