A carnot engine works between $600 K$ and $300 K$ . The efficiency of the engine is

50 %

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70 %

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20 %

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80 %

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Solution

The correct option is A $50 %$
Efficiency: $η = 1 - \frac{T_{2}}{T_{1}} = 1 - \frac{300}{600} = 1 - \frac{1}{2} = \frac{1}{2}$
Thus, percentage of efficiency is $50 %$

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A carnot engine works between 600K and 300K. The efficiency of the engine is

The correct option is A 50%Efficiency:η=1−T2T1=1−300600=1−12=12Thus, percentage of efficiency is 50%

A carnot engine works between $600 K$ and $300 K$ . The efficiency of the engine is

The correct option is A $50 %$
Efficiency: $η = 1 - \frac{T_{2}}{T_{1}} = 1 - \frac{300}{600} = 1 - \frac{1}{2} = \frac{1}{2}$
Thus, percentage of efficiency is $50 %$