A Carnot refrigerator requires 1-3 kW per ton of refrigeration to maintain a temperature if 40-C- What is the temperature at which heat is rejected and amount of heat rejected-

COP=Q_2W=3.51.3=2.69 for carnot cycle, COp=T_2T_1 T_2 nbsp; [Given: T_2= 40+273=233K] 2.69=233T_1 233 T_1=319.617 K and heat rejected, nbsp; Q_1=Q_2 ...

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A Carnot refr...

Question

A Carnot refrigerator requires 1.3 kW per ton of refrigeration to maintain a temperature if 40 $^{\circ}$ C. What is the temperature at which heat is rejected and amount of heat rejected?

319.617 K, 288 kJ/min

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233 K, 288 kJ/min

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319.617 K, 4.8 kJ/min

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233 K, 4.8 kJ/min

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Solution

The correct option is A 319.617 K, 288 kJ/min

$C O P = \frac{Q_{2}}{W} = \frac{3.5}{1.3} = 2.69$

$for carnot cycle, C O p = \frac{T_{2}}{T_{1} - T_{2}}$

$[G i v e n : T_{2} = - 40 + 273 = 233 K]$

$2.69 = \frac{233}{T_{1} - 233}$

$T_{1} = 319.617 K$

and heat rejected, $Q_{1} = Q_{2} + W$

$= 3.5 + 1.3 = 4.8 k W = 288 k J / m i n$

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A Carnot refrigerator requires 1.3 kW per ton of refrigeration to maintain a temperature if 40∘C. What is the temperature at which heat is rejected and amount of heat rejected?

The correct option is A 319.617 K, 288 kJ/min COP=Q2W=3.51.3=2.69 for carnot cycle,COp=T2T1−T2 [Given:T2=−40+273=233K] 2.69=233T1−233 T1=319.617K and heat rejected, Q1=Q2+W =3.5+1.3=4.8kW=288 kJ/min

A Carnot refrigerator requires 1.3 kW per ton of refrigeration to maintain a temperature if 40 $^{\circ}$ C. What is the temperature at which heat is rejected and amount of heat rejected?