A carpenter had a board which measured 3 m by 2m. she cut out a rectangular piece of 250 cm by 90 cm.
The ratio of the area of cut out piece and the remaining piece ___ .

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Solution

Length of board = 3 m or 300 cm
Breadth of board = 2 m or 200 cm
Area of board
$= 300 \times 200 = 60000 s q . c m$

Length of rectangular cut out = 250 cm
Breadth of rectangular cut out = 90 cm

Area of cut out
$= 250 \times 90 = 22500 s q . c m$

Area of remaining piece = 37500 sq.cm
$R a t i o = \frac{A r e a o f c u t o u t p i e c e}{A r e a o f r e m a i n i n g p i e c e}$
$= \frac{22500}{37500} = \frac{3}{5} o r 3 : 5$

Thus, the ratio of the area of the cutout piece and the remaining piece is 3:5.

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A carpenter had a board which measured 3 m by 2m. she cut out a rectangular piece of 250 cm by 90 cm. The ratio of the area of cut out piece and the remaining piece ___ .

A carpenter had a board which measured 3 m by 2m. she cut out a rectangular piece of 250 cm by 90 cm.
The ratio of the area of cut out piece and the remaining piece ___ .