A carpenter, while driving a screw through a wooden block, of thickness 1.5 cm, notices that he has to rotate the screw 20 times for the purpose. Then the pitch of the screw is:

0.015 cm

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0.75 cm

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0.15 cm

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0.075 cm

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Solution

The correct option is D
0.075 cm

We know, Pitch = $\frac{Distance travelled on the pitch scale}{No.of rotations of the head scale}$
Substituting values from the question, we get:
$Pitch = \frac{1.5 c m}{20} = 0.075 c m .$

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A carpenter, while driving a screw through a wooden block, of thickness 1.5 cm, notices that he has to rotate the screw 20 times for the purpose. Then the pitch of the screw is:

The correct option is D 0.075 cm We know, Pitch = Distance travelled on the pitch scaleNo.of rotations of the head scale Substituting values from the question, we get: Pitch=1.5 cm20=0.075 cm.

The correct option is D
0.075 cm

We know, Pitch = $\frac{Distance travelled on the pitch scale}{No.of rotations of the head scale}$
Substituting values from the question, we get:
$Pitch = \frac{1.5 c m}{20} = 0.075 c m .$