A carrier measures 10 m- 7 m- 5 m- Find the maximum number of wooden crates each measuring 2 m- 1 m- 0-5 m that can be transported inside the carrier-

Volume of the carrier = 10× 7× 5 nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; ...

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Standard VIII

Mathematics

Volume of a Cuboid

A carrier mea...

Question

A carrier measures $10 m \times 7 m \times 5 m .$ Find the maximum number of wooden crates each measuring $2 m \times 1 m \times 0.5 m$ that can be transported inside the carrier.

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Solution

Volume of the carrier $= 10 \times 7 \times 5$
$= 350 m^{3}$

Volume of each wooden crate $= 2 \times 1 \times 0.5$
$= 1 m^{3}$

So, number of wooden crates that can be transported
$= \frac{Volume of the carrier}{Volume of each wooden crate}$

$= \frac{350}{1}$

$= 350$

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A carrier measures 10 m×7 m×5 m. Find the maximum number of wooden crates each measuring 2 m×1 m×0.5 m that can be transported inside the carrier.

Volume of the carrier =10×7×5 =350 m3 Volume of each wooden crate =2×1×0.5 =1 m3 So, number of wooden crates that can be transported =Volume of the carrierVolume of each wooden crate =3501 =350

A carrier measures $10 m \times 7 m \times 5 m .$ Find the maximum number of wooden crates each measuring $2 m \times 1 m \times 0.5 m$ that can be transported inside the carrier.

Volume of the carrier $= 10 \times 7 \times 5$
$= 350 m^{3}$

Volume of each wooden crate $= 2 \times 1 \times 0.5$
$= 1 m^{3}$

So, number of wooden crates that can be transported
$= \frac{Volume of the carrier}{Volume of each wooden crate}$

$= \frac{350}{1}$

$= 350$