A carrier signal
$c (t) = 2 cos (2 π \times 10^{6} t)$ V and a message signal $m (t) = 2 cos (2000 π t)$ V are applied to a phase modulator whose phase sensitivity is $k_{p} = 1.5 r a d / V$ . The modualtion index of the resultant phase modulated signal will be

$3 \times 10^{3} r a d$

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1.5 rad

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$1.5 \times 10^{- 3} r a d$

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3 rad

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Solution

The correct option is D 3 rad
(a)
For a PM signal,
$β = | Δ ϕ |_{max} = k_{p} A_{m} = 2 (1.5) = 3 r a d$

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