wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A cart is being pulled up the incline, using a motor M and an ideal pulley and ideal rope arrangement as shown in figure. Then the speed of point ′P′ of the string with which it moves so that the car moves up the inclined plane with a constant speed of Vcart=2 m/s is (Incline is at rest):
75062_34edce2461ff44bc9d8c6230d1db6ba6.png

A
12 ms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3 ms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5 ms1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6 ms1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 6 ms1
We can see that three segments of the string which is supporting the cart is balanced by a single segment of string from motor M. So from pulley constraint relation, for a small displacement, x of string towards motor would produce x=3x displacement of cart.
Therefore x=3x
Differentiating, v=3v
Therefore, velocity of point P=3×2=6 m/s

110409_75062_ans_71189175e09544e88acd72eef23ed269.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motion Under Constant Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon