Question

A cart of mass $2.00kg$ is attached to the end of a horizontal spring with force constant $k=150N/m$. The cart is displaced $15.0cm$ from its equilibrium position and released. Neglect friction. Calculate the maximum velocity of the cart.

• A. $2.9m/s$
• B. $4.9m/s$
• C. $2.5m/s$
• D. $1.3m/s$

Answer 1

The correct option is D $1.3m/s$

$T=2\pi \sqrt{\frac{m}{k}}=2\pi \sqrt{\frac{2.0}{150}}=0.726$ s

$u_{max}=\omega A$
$=\left(\frac{2\pi }{T}\right)A=\left(\frac{2\pi }{0.726}\right)\left(0.15\right)$
$=1.30m/s$