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Standard XII

Physics

Periodic Motion

A cart of mas...

Question

A cart of mass $2.00 k g$ is attached to the end of a horizontal spring with force constant $k = 150 N / m$ . The cart is displaced $15.0 c m$ from its equilibrium position and released. Neglect friction. Calculate the frequency of oscillations.

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Solution

Frequency of oscillations, $f = \frac{1}{2 π} \sqrt{\frac{k}{m}} = \frac{1}{2 π} \sqrt{\frac{150}{2}} = \frac{4.33}{π}$

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A cart of mass 2.00 kg is attached to the end of a horizontal spring with force constant k=150 N/m. The cart is displaced 15.0 cm from its equilibrium position and released. Neglect friction. Calculate the frequency of oscillations.

Frequency of oscillations, f=12π√km=12π√1502=4.33π

A cart of mass $2.00 k g$ is attached to the end of a horizontal spring with force constant $k = 150 N / m$ . The cart is displaced $15.0 c m$ from its equilibrium position and released. Neglect friction. Calculate the frequency of oscillations.

Frequency of oscillations, $f = \frac{1}{2 π} \sqrt{\frac{k}{m}} = \frac{1}{2 π} \sqrt{\frac{150}{2}} = \frac{4.33}{π}$