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Question

A cart of weight 10 N is pulled 1.2 m up a ramp by an applied force of magnitude 5.0 N (parallel to the ramp), raising the cart 0.50 m above its initial level. Calculate percentage efficiency of the work?


A

83.33%

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B

85%

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C

84.5%

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D

86.33%

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Solution

The correct option is A

83.33%


Given, weight of the cart (mg) = 10 N, vertical displacement (h)= 0.5 m and distance covered on the ramp (s)=1.2 m.

Energy output = Potential energy
=m×g×h
=10×0.5=5J

Energy input = Work done to move the cart
= Force × distance covered on the ramp
= 5 × 1.2 = 6 J
Percentage efficiency =Energy outputEnergy input
= 56 ×100
= 83.33%


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