A carton contains $20$ bulbs, $5$ of which are defective. The probability that, if a sample of $3$ bulbs is chosen at random from the carton $2$ will be defective is

3 / 64

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5 / 38

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Solution

The correct option is D $5 / 38$
Total bulbs =20 (5 defective +15 non-defective)
Total cases $=^{20} C_{3}$
Favourable cases $=^{5} C_{2} \times^{15} C_{1}$
Required probability $= \frac{^{5} C_{2} \times^{15} C_{1}}{^{20} C_{3}}$ $= \frac{5}{38}$

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Q. Question 18
Bulbs are packed in cartons each containing 40 bulbs. Seven hundred cartons were examined for defective bulbs and the results are given in the following table.

\begin{matrix} N u m b e r o f & 0 & 1 & 2 & 3 & 4 & 5 & 6 & M o r e d e f e c t i v e & t h a n 6 b u l b s F r e q u e n c y & 400 & 180 & 48 & 41 & 18 & 8 & 3 & 2 \end{matrix}

One carton was selected at random. What is the probability that it has
(i) No defective bulb?

(ii) Defective bulbs from 2 - 6?

(iii) Defective bulbs less than 4?

Bulbs are packed in cartons each containing 40 bulbs. Seven hundred cartons were examined for defective bulbs and the results are given in the following table:

No. of defective bulbs	0	1	2	3	4	5	6	more than 6
frequency	400	180	48	41	18	8	3	2

One carton was selected at random. What is the probability that it has more than 1 defective bulbs?

Q. A carton of 26 bulbs contains 6 defective bulbs. One bulb is drawn at random. If the selected bulb is defective, what is the probability that the second bulb drawn is defective?

Question 18
Bulbs are packed in cartons each containing 40 bulbs. Seven hundred cartons were examined for defective bulbs and the results are given in the following table.

$\begin{matrix} Number of & 0 & 1 & 2 & 3 & 4 & 5 & 6 & More defective & than 6 bulbs Frequency & 400 & 180 & 48 & 41 & 18 & 8 & 3 & 2 \end{matrix}$

One carton was selected at random. What is the probability that it has
(i) No defective bulb?

(ii) Defective bulbs from 2 - 6?

(iii) Defective bulbs less than 4?

Question 18
Bulbs are packed in cartons each containing 40 bulbs. Seven hundred cartons were examined for defective bulbs and the results are given in the following table.

$\begin{matrix} Number of & 0 & 1 & 2 & 3 & 4 & 5 & 6 & More defective & than 6 bulbs Frequency & 400 & 180 & 48 & 41 & 18 & 8 & 3 & 2 \end{matrix}$

One carton was selected at random. What is the probability that it has
(i) No defective bulb?

(ii) Defective bulbs from 2 - 6?

(iii) Defective bulbs less than 4?

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A carton contains 20 bulbs, 5 of which are defective. The probability that, if a sample of 3 bulbs is chosen at random from the carton 2 will be defective is

The correct option is D 5/38Total bulbs =20 (5 defective +15 non-defective)Total cases =20C3Favourable cases =5C2×15C1Required probability =5C2×15C120C3 =538

A carton contains $20$ bulbs, $5$ of which are defective. The probability that, if a sample of $3$ bulbs is chosen at random from the carton $2$ will be defective is

The correct option is D $5 / 38$
Total bulbs =20 (5 defective +15 non-defective)
Total cases $=^{20} C_{3}$
Favourable cases $=^{5} C_{2} \times^{15} C_{1}$
Required probability $= \frac{^{5} C_{2} \times^{15} C_{1}}{^{20} C_{3}}$ $= \frac{5}{38}$