A cask contains 3parts ale and 1 part porter. How much of the mixture must be drawn off and porter substituted in order that the resulting mixture may be half and half?

\frac{1}{3}

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\frac{1}{2}

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\frac{1}{5}

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\frac{1}{6}

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Solution

The correct option is A $\frac{1}{3}$
$\frac{1}{4} : \frac{1}{2}$
$\Rightarrow \frac{1}{2} : 1$
$\Rightarrow \frac{1}{3}$
The given answer is correct.

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A cask contains 3parts ale and 1 part porter. How much of the mixture must be drawn off and porter substituted in order that the resulting mixture may be half and half?

The correct option is A 1314:12⇒12:1⇒13The given answer is correct.

The correct option is A $\frac{1}{3}$
$\frac{1}{4} : \frac{1}{2}$
$\Rightarrow \frac{1}{2} : 1$
$\Rightarrow \frac{1}{3}$
The given answer is correct.