Question

A cathode ray particle is accelerated from rest through a potential difference of 'V' volt. Speed of the particle is

• A. $\sqrt{\frac{2eV}{m}}$
• B. $\frac{m}{eV}$
• C. $\sqrt{meV}$
• D. $\sqrt{\frac{4eV}{m}}$

Answer 1

The correct option is A $\sqrt{\frac{2eV}{m}}$

W = eV = KE
mass of the particle = m
speed of the particle = $v$
$\frac{1}{2}m{v}^2=eV$
So, $v$ = $\sqrt{\frac{2eV}{m}}$