A ceiling has a shape of rhombus whose diagonals lengths are $10$ cm & $20$ cm. How many such tiles are required to cover ceiling of area $1000 m^{2}$ .

10^{3}

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10^{4}

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10^{5}

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10^{6}

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Solution

The correct option is B $10^{5}$
As we know that the number of tiles x Area of each tile = Area of ceiling
Area of each tile $= \frac{1}{2} \times d_{1} \times d_{2} = \frac{1}{2} \times 10 \times 20 = 100 {c m}^{2}$
Thus, number of tiles $= \frac{1000 m^{2}}{100 {c m}^{2}} = \frac{10000 \times 1000}{100} \frac{{c m}^{2}}{{c m}^{2}} = 10^{5}$

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A ceiling has a shape of rhombus whose diagonals lengths are 10cm & 20 cm. How many such tiles are required to cover ceiling of area 1000m2.

The correct option is B 105As we know that the number of tiles x Area of each tile = Area of ceilingArea of each tile =12×d1×d2=12×10×20=100cm2Thus, number of tiles =1000m2100cm2=10000×1000100cm2cm2=105

A ceiling has a shape of rhombus whose diagonals lengths are $10$ cm & $20$ cm. How many such tiles are required to cover ceiling of area $1000 m^{2}$ .