A cell A has an osmotic potential of -20 bar and a pressure potential of +6 bar. What will be its water potential?

–14 bar

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

+ 14 bar

No worries! We‘ve got your back. Try BYJU‘S free classes today!

–20 bar

No worries! We‘ve got your back. Try BYJU‘S free classes today!

–36 bar

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A –14 bar
Water potential $ψ = ψ_{s} + ψ_{p}$
$= - 20 + 6 = - 14$ bar

Suggest Corrections

Similar questions

The cell A has an osmotic potential of-20 bars and a pressure potential of + 6 bars. What will be its water potential?

Cell A has an osmotic potential of −18 bars and a pressure potential of 8 bars, whereas cell B has an osmotic potential of −14 bars and a pressure potential of 2 bars. The direction of flow of water will be

Q. Cell-A has osmotic potential of –18 bars and pressure potential of 8 bars, whereas, cell-B has osmotic potential of –14 bars and pressure potential 2 bars. The direction of flow of water will be

Q. Cell A has osmotic potential of –18 bars and pressure potential of 8 bars, whereas cell B has osmotic potential of –14 bars and pressure potential 2 bars. The direction of flow of water will be

There are 2 adjacent living cells A & B. The cell ‘A’ has osmotic potential ( $Ψ$ s) of - 7 bars, and pressure potential ( $Ψ_{p}$ ) of 5 bars, whereas cell ‘B’ has osmotic potential ( $Ψ_{s}$ ) of – 8 bars and pressure potential ( $Ψ_{p}$ ) of 3 bars, what will be the direction of water flow in these cells?

Join BYJU'S Learning Program

A cell A has an osmotic potential of -20 bar and a pressure potential of +6 bar. What will be its water potential?

The correct option is A –14 barWater potential ψ=ψs+ψp =−20+6=−14 bar

The correct option is A –14 bar
Water potential $ψ = ψ_{s} + ψ_{p}$
$= - 20 + 6 = - 14$ bar