A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively with and without being short circuited through a resistance of 10 . Its internal resistance is -
A
2.0 ohm
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B
zero
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C
1.0 ohm
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D
0.5 ohm
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Solution
The correct option is B 1.0 ohm E∝l1andE−ER+r.r∝l2 ⇒r+RR=l1l2 ⇒r=(l1l2−1).R =110−100100×10=1Ω