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Question

A cell contains two hydrogen electrode. The negative electrode is in contact with a solution of 106 M hydrogen ions. the EMF of the cell is 0.118 V at 25oC. If the concentration of hydrogen ions at the positive electrode is x×105 M, then the value of x is

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Solution

Here we are considering a concentration cell as both the electrodes are made of same element.
For a concentration cell,
Ecell=0.059nlogC1C2
At anode; H22H++2e [H+]=106 M
At cathode; 2H++2eH2
So,
Ecell=0.0591log[CH+106]
0.118=0.0591log[CH+106]
log[CH+106]=0.1180.059=2
Therefore, [CH+]=104 M
So the vale of x will be 10

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