A cell emf 1-5V and internal resistance 1-0 - is connected to two resistors of 4-0 - and 20-0 - in series as shown in the figure-

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Byju's Answer

Standard XII

Physics

Inductors in Circuits

A cell emf 1....

Question

A cell emf 1.5V and internal resistance 1.0 $Ω$ is connected to two resistors of 4.0 $Ω$ and 20.0 $Ω$ in series as shown in the figure:

current in the circuit is 0.05 A

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potential difference across the 4.0 ohm resistor is 0.2 V

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voltage drop, when the current is flowing is 0.06 V

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potential difference across the cell is 1.14 V

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Solution

The correct options are
C voltage drop, when the current is flowing is 0.06 V
D potential difference across the cell is 1.14 V

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A cell emf 1.5V and internal resistance 1.0Ω is connected to two resistors of 4.0Ω and 20.0Ω in series as shown in the figure:

The correct options are C voltage drop, when the current is flowing is 0.06 V D potential difference across the cell is 1.14 V

A cell emf 1.5V and internal resistance 1.0 $Ω$ is connected to two resistors of 4.0 $Ω$ and 20.0 $Ω$ in series as shown in the figure:

The correct options are
C voltage drop, when the current is flowing is 0.06 V
D potential difference across the cell is 1.14 V