A cell has an emf 1-5 V- When connected across an external resistance of 2 - the terminal potential difference forces to 1 V- The internal resistance of the cell isA- 1 -B- 0-5 -C- 2 -D- 1-52 -

The correct option is A 1 Ω 1.5 I R_i = 1 ⇒ IR_i = 1.5 1 = 0.5 V ⇒1.5/2+R_i.R_i = 0.5 ⇒ 1.5 R_i = 1+0.5 R_i ⇒ R_i=1 Ω ...

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Standard X

Physics

Ohm's Law

A cell has an...

Question

A cell has an emf 1.5 V. When connected across an external resistance of $2 Ω$ , the terminal potential difference forces to 1V. The internal resistance of the cell is

2 Ω

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1.52 Ω

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1 Ω

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0.5 Ω

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Solution

The correct option is C $1 Ω$

$1.5 - I R_{i} = 1 \Rightarrow I R_{i} = 1.5 - 1 = 0.5 V \Rightarrow \frac{1.5}{2 + R_{i}} . R_{i} = 0.5 \Rightarrow 1.5 R_{i} = 1 + 0.5 R_{i} \Rightarrow R_{i} = 1 Ω$

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A cell has an emf 1.5 V. When connected across an external resistance of 2Ω, the terminal potential difference forces to 1V. The internal resistance of the cell is

The correct option is C 1Ω 1.5−IRi=1⇒IRi=1.5−1=0.5V⇒1.52+Ri.Ri=0.5⇒1.5Ri=1+0.5Ri⇒Ri=1Ω

A cell has an emf 1.5 V. When connected across an external resistance of $2 Ω$ , the terminal potential difference forces to 1V. The internal resistance of the cell is

The correct option is C $1 Ω$

$1.5 - I R_{i} = 1 \Rightarrow I R_{i} = 1.5 - 1 = 0.5 V \Rightarrow \frac{1.5}{2 + R_{i}} . R_{i} = 0.5 \Rightarrow 1.5 R_{i} = 1 + 0.5 R_{i} \Rightarrow R_{i} = 1 Ω$