wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A cell is formed by immersing two Cd electrodes in CdSO4 solutions having concentrations of 0.1 M and 0.5 M at 25C.
Which of the following(s) is/are true for the given cell?

Take:
log 50.7

A
Ecell=0.02
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Ecell=0.20
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Cell representation for spontaneous cell is
Cd(s)|Cd2+(aq, 0.1 M)||Cd2+(aq, 0.5 M)|Cd(s)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Cell representation for spontaneous cell is
Cd(s)|Cd2+(aq, 0.5 M)||Cd2+(aq, 0.1 M)|Cd(s)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Cell representation for spontaneous cell is
Cd(s)|Cd2+(aq, 0.1 M)||Cd2+(aq, 0.5 M)|Cd(s)
In concentration cell, for a spontaneous process, the electrode with higher concentration of electrolyte will act as cathode and lower concentration half cell will act as anode.

Thus, the cell represented as,
Cd(s)|Cd2+(aq, 0.1 M)||Cd2+(aq, 0.5 M)|Cd(s)

The electrode half cell reaction will be
Cd2+(aq, 0.5 M)+2eCd(s)
Cd(s)Cd2+(aq, 0.1 M)+2e

The cell reaction will be
Cd2+(aq, 0.5 M)Cd2+(aq, 0.1 M)

By Nernst equation,

Ecell=E0cell0.0592 log 0.10.5

For concentration cells,
E0cell=0

Ecell=0.0592 log 0.10.5

Ecell=0.0592 log 0.50.1

Ecell=0.0592 log 5

Ecell=0.0592×0.7

Ecell=0.02 V


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon