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Question

A cell is represented by
ZnZn2+(aq)Cu2+(aq)Cu.
Given, Cu2++2eCu,E=+0.35V and Zn2++2eZn,E=0.763V. Write the cell reactions, emf of the cell and state whether the cell reaction will be spontaneous or not?

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Solution

The given cell is
ZnZn2+(aq)Cu2+(aq)Cu
Half-cell reaction at anode
ZnZn2++2e [oxidation]
Half-cell reaction at cathode [reduction]
Cu2++2eCu
Overall reaction, Zn+Cu2+Zn2++Cu
Ecell=EREL
=ECu2+/uEZn2+/Zn
=0.35(0.763)
Ecell=1.113V
Positive value of Ecell shows, cell reaction is spontaneous.

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