A cell of emf 2V delivers current equal to 20% of the maximum current, which it can produce through a resistance 4 Ω. Its internal resistance is
A
0.1Ω
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B
1Ω
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C
0.5Ω
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D
1.5Ω
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Solution
The correct option is C 1Ω Case 1 max account ⇒E=Imax(R) Case 2 20% of max current ⇒E=Imaxx0.2(R+r) R - Internal resistance r=−4Ω ⇒R=0.2R+0.2r 0.8R=0.2×4 R=0.80.8=1Ω