A cell of emf 3 V and internal resistance 075 Ω is connected to a nonlinear conductor whose VI graph is shown in figure obtain graphically the current drawn from the cell.
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Solution
Here draw a straight line V=E−Ir where E=3V,r=0.75Ω as shown in figure. when I=0,V=3 and when V=0,I=4A The intersection of this line with V-I plot for the conductor gives the current 2 A.