A cell of emf E having an internal resistance r is connected to an external resistance R. The potential difference V across the resistance R varies with R as shown by the curve:

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Solution

The correct option is B B
$V = E - i r = - \frac{E r}{R + r} = E [\frac{R + r - r}{R + r}] V = \frac{E R}{(R + r)} \Rightarrow V = 0 a t R = 0 V = E a t R = \infty$

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A cell of emf E having an internal resistance r is connected to an external resistance R. The potential difference V across the resistance R varies with R as shown by the curve:

The correct option is B BV=E−ir=−ErR+r=E[R+r−rR+r]V=ER(R+r)⇒V=0 at R=0V=E at R=∞

The correct option is B B
$V = E - i r = - \frac{E r}{R + r} = E [\frac{R + r - r}{R + r}] V = \frac{E R}{(R + r)} \Rightarrow V = 0 a t R = 0 V = E a t R = \infty$