wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A cell of internal resistance r is connected to a load of resistance R. Energy is dissipated in the load but some thermal energy is also wasted in the cell. The efficiency of such an arrangement is found from the expression

Energy dissipated in the loadEnergy dissipated in the complete circuit

Which of the following gives the efficiency in this case?

A
rR
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Rr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
rR+r
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
RR+r
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D RR+r
Let El and Ec be the energies dissipated in the load and in the complete circuit respectively.
Let I be the current flowing through the circuit.


El=I2R
El=E2(R+r)2×R......(i)

Similarly, Ec=E2(R+r)2×(R+r)...(ii)
Efficiency = R(R+r)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon