A cell of potential difference $12 V$ is connected to a bulb. The resistance of filament of bulb when it glows, is $24$ $Ω$ . The current drawn from the cell is

2 A

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1.5 A

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0.5 A

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1 A

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Solution

The correct option is B 0.5 A
According to the Ohm's law, the value of current is given as: $I = V / R$
The potential difference is $12 V$ and the resistance of filament of bulb when it glows, is $24 Ω$ .
Hence, the current drawn from the cell is: $I = \frac{12 V}{24 Ω} = 0.5 A$

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A cell of potential difference 12 V is connected to a bulb. The resistance of filament of bulb when it glows, is 24 Ω. The current drawn from the cell is

The correct option is B 0.5 AAccording to the Ohm's law, the value of current is given as: I=V/RThe potential difference is 12 V and the resistance of filament of bulb when it glows, is 24 Ω. Hence, the current drawn from the cell is: I=12V24Ω=0.5 A

A cell of potential difference $12 V$ is connected to a bulb. The resistance of filament of bulb when it glows, is $24$ $Ω$ . The current drawn from the cell is

The correct option is B 0.5 A
According to the Ohm's law, the value of current is given as: $I = V / R$
The potential difference is $12 V$ and the resistance of filament of bulb when it glows, is $24 Ω$ .
Hence, the current drawn from the cell is: $I = \frac{12 V}{24 Ω} = 0.5 A$