A cell sends a current i1 through a coil of resistance R1 and a current i2 through a coil of resistance is R2.The emf of the cell is
A
i1i2(i1+i2)(R1+R2)
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B
i1i2(i1−i2)(R1−R2)
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C
i2R2−i1R1i1+i2
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D
i2R2−i2R1R1+R2
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Solution
The correct option is Bi1i2(i1−i2)(R1−R2) i1=ER1+r where r is the terminal resistance of the cell. r=E−i1R1i1Ori2=ER2+r Also E=i2R2+i2r=i2R2+i2(E−i1R1i1) Simplifying, we get E=i1i2(R2−R1)i1−i2