A cell supplies a current of 0.9A through a 2Ω resistor and a current of 0.3A through a 7Ω resistor. The internal resistance of the cell is :-
A
1.0Ω
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B
0.5Ω
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C
2.0Ω
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D
1.2Ω
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Solution
The correct option is B0.5Ω Let E be the emf of cell and r be the internal resistance. here, E=0.9(2+r)...(1) and E=0.3(7+r)...(2) From (1) and (2), 0.9(2+r)=0.3(7+r) or 1.8+0.9r=2.1+0.3r or 0.6r=0.3 or r=0.5Ω