Question

A cement concrete pavement has thickness of 25 cm and of two lanes with a longitudinal joint along the centre. if the coefficient of friction (f) is 1.5 then the area of steel required per meter is ______ $c{m}^2$
$[Take{\gamma }_{concrete}=2400kg/m^{3}and{\sigma }_s=1400kg/c{m}^2,\text{width of pavement,}w=3.5m]$

Answer 1

Given, h = 25 cm, w = 3.5 m/lane

$A_s=\frac{bfh\gamma }{100{\sigma }_s}=\frac{3.5\times 1.5\times 2400\times 25}{100\times 1400}$
$=2.25{\text{cm}}^2/m$