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A cement conc...

Question

A cement concrete pavement has thickness of $25 cm$ and of two lanes with a longitudinal joint along the centre. if the coefficient of friction (f) is 1.5 then the area of steel required per meter is $c m^{2}$ [Take $γ_{c o n c r e t e} = 2400 k g / m^{3}$ and $σ_{s} = 1400 k g / c m^{2}$ , width of pavement, w = 3.5 m]

2.25

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Solution

The correct option is A 2.25
Given, $h = 25 cm, w = 3.5 m/lane$
$A_{s} = \frac{b f h γ}{100 σ_{s}} = \frac{3.5 \times 1.5 \times 2400 \times 25}{100 \times 1400} = 2.25 {cm}^{2} / m$

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