Question

A Centrifuge rotor is accelerated from Rest to 21000 RPM in 3 minutes 30 seconds the angular acceleration in rad/sec^{​​​​2} is how much ?

Answer 1

angular acceleration = change in angular velocity / time

given accelerated from rest ,so initial angular velocity = 0 rad/sec

given final RPM

therfore final angular velocity =( 2*pi *RPM) / 60

= (2*3.14*21000) / 60 = 2198 rad/sec

given time 3 min 30 sec = 3*60 + 30 sec = 210 sec

angular acceleration = (2198 - 0) / 210 = 10.4667 rad/sec^{​​​​2}