A certain amount of gas at $27^{\circ} C$ and one bar pressure occupied a volume of 25m cube if pressure cept constatnt temperature raised to $77^{\circ} C$ . what will be volume of gas ?

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Solution

We know,
$V_{1} T_{1} = V_{2} T_{2}$
Here,
$V_{1} = 25 m^{3}$
$T_{1} = 27^{0} C = 300 K$
$T_{2} = 77^{0} C = 350 K$
Hence,
$V_{2} = \frac{V_{1} T_{1}}{T_{2}} = \frac{25 \times 300}{350} = 21.43 m^{3}$

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A certain amount of gas at 27∘C and one bar pressure occupied a volume of 25m cube if pressure cept constatnt temperature raised to 77∘C. what will be volume of gas ?

We know,V1T1=V2T2Here,V1=25m3T1=270C=300KT2=770C=350KHence,V2=V1T1T2=25×300350=21.43m3

A certain amount of gas at $27^{\circ} C$ and one bar pressure occupied a volume of 25m cube if pressure cept constatnt temperature raised to $77^{\circ} C$ . what will be volume of gas ?

We know,
$V_{1} T_{1} = V_{2} T_{2}$
Here,
$V_{1} = 25 m^{3}$
$T_{1} = 27^{0} C = 300 K$
$T_{2} = 77^{0} C = 350 K$
Hence,
$V_{2} = \frac{V_{1} T_{1}}{T_{2}} = \frac{25 \times 300}{350} = 21.43 m^{3}$